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What is the value of \(\lim\limits_{y \rightarrow 0}\)(32 x^2 cosec^2 ⁡4x)?(a) 1(b) 4(c) 2(d) 3The question was posed to me in semester exam.My doubt stems from Limits of Trigonometric Functions in portion Limits and Derivatives of Mathematics – Class 11

Answer»

Correct CHOICE is (c) 2

For explanation I would say: The limit can be WRITTEN as, \(\lim\limits_{X \rightarrow 0}\FRAC{32x^2}{sin^2⁡4X}\)

= 2 x \(\lim\limits_{x \rightarrow 0}\frac{4x}{sin 4x}\) x \(\lim\limits_{x \rightarrow 0}\frac{4x}{sin 4x}\)

= 2 x 1 x 1

= 2



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