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What is the value of \(\lim\limits_{y \rightarrow 4}\) f(y)? It is given that f(y) = y^2 + 6y (y ≥ 2) and f(y) = 0 (y < 2).(a) 40(b) 16(c) 0(d) 30I got this question in exam.My query is from Limits topic in section Limits and Derivatives of Mathematics – Class 11

Answer»

The CORRECT answer is (a) 40

Explanation: \(\lim\limits_{y \RIGHTARROW 4}\)f(y) = y^2 + 6y

f(4) = 4^2 + 6(4)

f(4) = 16 + 24

f(4) = 40



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