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What is the value of \(\lim\limits_{y \rightarrow \pi/2}\frac{sin⁡ x}{x}\)?(a) \(\frac{2}{\pi}\)(b) \(\frac{\pi}{2}\)(c) 1(d) 0The question was posed to me in an internship interview.Enquiry is from Limits of Trigonometric Functions topic in portion Limits and Derivatives of Mathematics – Class 11

Answer»

The correct option is (a) \(\frac{2}{\pi}\)

To explain I WOULD say: SIN ⁡\(\frac{\pi}{2}\) = 1

\(\lim\limits_{y \rightarrow \pi/2}\frac{sin⁡x}{x} = \frac{sin⁡\frac{π}{2}}{\frac{\pi}{2}}\)

= \(\frac{1}{\frac{\pi}{2}}\)

= \(\frac{2}{\pi}\)



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