1.

What is the value of shunt resistance required to convert a galvanometer of resistance 100 Omega into an ammeter of range 1 A ? Given: Full scale deflection of thegalvanometer is 5 mA.

Answer»

`(5)/(9.95) OMEGA`
`(9.95)/(5) Omega`
`0.5 Omega`
`0.05 Omega`

SOLUTION :`S = (I_(G)G)/(I-I_(g)) = (5 XX 10^(-3) xx 10^(2))/(1-5 xx 10^(-3)) = (0.5)/(1-5 xx 10^(-3)) = (5)/(10-0.05) = (5)/(9.95) Omega`


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