1.

What is the value of slope of graph log_(10)Kto(1)/(T)?

Answer»

`-(K)/(2.303)`
`-(E_(a))/(2.303R)`
`-(E-(a))/(R)`
`-K`

Solution :According to ARRHENIUS
`k=e^(-E_(a)//RT)`
`therefore` In k=`-(E_(a))/(R )`+In A


`therefore` If the graph of log k`to(1)/(T)` is to be drawn then , SLOPE =`-(E_(a))/(2.303R)` and intersection =A


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