1.

What is the value of the \(\lim\limits_{x \rightarrow \frac{3\pi}{2}}\frac{cos⁡ x sin⁡ x}{sin⁡2x}\)?(a) \(\frac{-1}{2}\)(b) \(\frac{1}{2}\)(c) \(\frac{1}{4}\)(d) \(\frac{-1}{4}\)I got this question during an internship interview.The question is from Limits of Trigonometric Functions topic in chapter Limits and Derivatives of Mathematics – Class 11

Answer»

Correct option is (b) \(\frac{1}{2}\)

To explain I WOULD say: \(\lim\limits_{x \RIGHTARROW \frac{3\pi}{2}}\frac{COS⁡ x sin⁡ x}{sin⁡2x}\) =\(\lim\limits_{x \rightarrow \frac{3\pi}{2}}\frac{cos⁡ x sin⁡ x}{2 cos x sin⁡ x}\)

= \(\frac{1}{2}\)



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