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What is the value of the limit \(\lim\limits_{x \rightarrow 4}\frac{x^2-4-3x}{x-3}\)?(a) 0(b) 4(c) 1(d) Limit does not existThe question was posed to me by my college director while I was bunking the class.The above asked question is from Limits topic in portion Limits and Derivatives of Mathematics – Class 11

Answer»

The correct CHOICE is (a) 0

To elaborate: \(\lim\limits_{X \rightarrow 4}\frac{x^2-4-3x}{x-3}\)

= \(\frac{4^2-4-3(4)}{4-3}\)

= \(\frac{0}{1}\)

= 0.



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