1.

What is the value of voltage VB of a CC amplifier configuration if VCC = 12V, R1 = 5kΩ and R2 = 8kΩ?(a) 6.54V(b) 0.7V(c) 4.6V(d) 7.38VI had been asked this question in an online interview.My doubt is from Simplified Calculations for the CC Configuration in portion Low Frequency Transistor Amplifier Circuit of Electronic Devices & Circuits

Answer»

Correct option is (d) 7.38V

To explain I would say: The voltage VB of a simplified common collector AMPLIFIER configuration can be calculated using VB = I × R2. GIVEN, VCC = 12V and R1 = 5kΩ and R2 = 8kΩ:

I = VCC / R1 + R2 = 12 / (5 + 8) = 0.92mA

VB = I × R2 = 0.92mA × 8kΩ = 7.38V



Discussion

No Comment Found

Related InterviewSolutions