1.

What is the value of |X(ω)| given X(ω)=1/(1-ae^-jω), |a|

Answer» CORRECT ANSWER is (a) \(\frac{1}{\sqrt{1-2acosω+a^2}}\)

To elaborate: For the GIVEN X(ω)=1/(1-ae^-jω), |a|<1 we obtain

XI(ω)=(-asinω)/(1-2acosω+a^2) and XR(ω)=(1-acosω)/(1-2acosω+a^2)

We know that |X(ω)|=\(\sqrt{X_R (ω)^2+X_I (ω)^2}\)

Thus on CALCULATING, we obtain

|X(ω)| =\(\frac{1}{\sqrt{1-2acosω+a^2}}\).


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