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What is the value of x when the Wheatstone's network is balanced? P=500Omega, Q=800Omega, R=x+400, S=1000Omega |
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Answer» <P> SOLUTION : `(P)/(Q)=(R )/(S)` `(500)/(800)=(x+400)/(1000)` `(x+400)/(1000)=(500)/(800)` `x+400=(500)/(800)xx1000=(5)/(8)xx1000` `x+400=0.625 xx1000` `x+400=625` `x=625-400` `x=225Omega` |
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