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What is the Van’t Hoff Factor for 1 mole of BaCl2, assuming 100% dissociation?(a) 0.33(b) 1(c) 3(d) 2I had been asked this question in an internship interview.This interesting question is from Abnormal Molar Masses topic in section Solutions of Chemistry – Class 12

Answer»

Right answer is (c) 3

Best explanation: VAN’t Hoff Factor can also be WRITTEN as the ratio between the total number of moles of particles after association / DISSOCIATION and the total number of moles of particles before association / dissociation. Since BACL2 COMPLETELY dissociates(into one Ba^2+ and two Cl^– ions), the total number of moles after dissociation is equal to 3. Therefore, the Van’t Hoff Factor for BaCl2 is 3.



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