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InterviewSolution
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What is the work done in taking a north pole of strength m around a long and straight conductor in a circular path at a perpendicular distance of r from the straight conductor? |
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Answer» Solution :`mu_0` im, since the FORCE acting on the north pole is `F = mB = (m mu_0 i)/(2pir)` along the tangent and the work DONE `= vec (F),vec(S)` = FS COS 0 as both force and displacmentare long the same direction. Hence , work done `= (mu_0 i)/(2PI r) (2pi r) = mu_0 `im. |
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