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| 1. |
What is work done on dipole to rotate it form stable equilibrium position `(theta_(1) = 0^(@))` to unstable equilibrium `(theta_(2) = 180^(@))` ? |
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Answer» w = MB `(cos theta_(1) - cos theta_(2))` `= MB [cos 0^(@) - cos 180^(@)]` =` MB[1-(-1)]` w = 2 MB |
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