1.

What mass of .^(226)Ra, whose t_(1//2)=1620 years will give the activity of 1 millicuries ?

Answer»

Solution :Activity `=(0.693)/(t_(1//2))XX(W)/(At.wt.)xx6.023xx10^(23)`
`implies3.7xx10^(7)=(0.693)/(1620xx365xx24xx3600)xx(W)/(256)xx6.023xx10^(23)`
`:.W=10^(-3)g`.


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