what must be subtracted from x^3-6x^2-15x+80 so that the result is exactly divisible by x^2+x-12 by factor theorem

what must be subtracted from x^3-6x^2-15x+80 so that the result is exa

1.	what must be subtracted from x^3-6x^2-15x+80 so that the result is exactly divisible by x^2+x-12 by factor theorem
Answer» <html><body><p>So, from the condition given in the question, we get to know that the dividend should be ${{x}^{3}}-6{{x}^{<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>}}-15x+80$ and the divisor should be ${{x}^{2}}+x-12$. ... Hence, (<a href="https://interviewquestions.tuteehub.com/tag/4x-319255" style="font-weight:bold;" target="_blank" title="Click to know more about 4X">4X</a> - 4) is the term that must be subtracted from ${{x}^{3}}-6{{x}^{2}}-15x+80$ so that the <a href="https://interviewquestions.tuteehub.com/tag/result-1187343" style="font-weight:bold;" target="_blank" title="Click to know more about RESULT">RESULT</a> is <a href="https://interviewquestions.tuteehub.com/tag/exactly-977868" style="font-weight:bold;" target="_blank" title="Click to know more about EXACTLY">EXACTLY</a> <a href="https://interviewquestions.tuteehub.com/tag/divisible-2588966" style="font-weight:bold;" target="_blank" title="Click to know more about DIVISIBLE">DIVISIBLE</a> by ${{x}^{2}}+x-12$.Step-by-step explanation:</p></body></html>