

InterviewSolution
Saved Bookmarks
1. |
What per cent `T_(1)` is of `T_(2)` for a heat engine whose efficiency is `10%`A. `92%`B. `10%`C. `90%`D. `100%` |
Answer» Correct Answer - C `eta=1-(T_(1))/(T_(2))` `(T_(1))/(T_(2))=1-eta=1-0.10=0.90=90%` `T_(1)=90% T_(2)` |
|