What percentage `T_(1)` is of `T_(2)` for a `10%` efficiency of a heat engine? `T_(1)` is the temperature of sink and `T_(2)` is the temperature of heat reservoir.A. `T_(1)=90%` of `T_(2)`B. `T_(1)=T_(2)`C. `T_(2)=90%` of `T_(1)`D. `T_(1)=50%` of `T_(2)`

What percentage `T_(1)` is of `T_(2)` for a `10%` efficiency of a heat

1.	What percentage `T_(1)` is of `T_(2)` for a `10%` efficiency of a heat engine? `T_(1)` is the temperature of sink and `T_(2)` is the temperature of heat reservoir.A. `T_(1)=90%` of `T_(2)`B. `T_(1)=T_(2)`C. `T_(2)=90%` of `T_(1)`D. `T_(1)=50%` of `T_(2)`
Answer» Correct Answer - C Efficiency, `eta=(T_(2)-T_(1))/(T_(2)=1-(T_(1))/(T_(2))=0.1` or `T_(1)=0.9T_(2)`

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What percentage `T_(1)` is of `T_(2)` for a `10%` efficiency of a heat engine? `T_(1)` is the temperature of sink and `T_(2)` is the temperature of heat reservoir.A. `T_(1)=90%` of `T_(2)`B. `T_(1)=T_(2)`C. `T_(2)=90%` of `T_(1)`D. `T_(1)=50%` of `T_(2)`

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