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What pressure should be applied to a lead block to reduce its volume by 10%? (Bulk modulus of lead =6 xx 10^9 N/m^2) |
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Answer» Solution :K = `vdp//dv` `THEREFOR` `DP = Kdv/v `6 xx 10^9 xx 10/100 = 6 xx 10^8 N/m^2` |
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