What property this does this equation come under \(\int^1_{-1}\)sin⁡x dx=-\(\int_1^{-1}\)sin⁡x dx?(a) Reverse integral property(b) Adding intervals property(c) Zero-length interval property(d) Adding integrand propertyI got this question during an online exam.Query is from Properties of Definite Integrals topic in section Integrals of Mathematics – Class 12

What property this does this equation come under \(\int^1_{-1}\)sin⁡

1.	What property this does this equation come under \(\int^1_{-1}\)sin⁡x dx=-\(\int_1^{-1}\)sin⁡x dx?(a) Reverse integral property(b) Adding intervals property(c) Zero-length interval property(d) Adding integrand propertyI got this question during an online exam.Query is from Properties of Definite Integrals topic in section Integrals of Mathematics – Class 12
Answer» Right choice is (a) Reverse integral PROPERTY The BEST explanation: \(\int^1_{-1}\)sin⁡X dx=-\(\int_1^{-1}\)sin⁡x dx comes under the reverse integral property. In the reverse integral property the upper limits and lower limits are INTERCHANGED. The reverse integral property of definite integrals is \(\int_a^b\)f(x)dx=-\(\int_b^a\)f(x)dx.

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