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What should be added to(1 by 2 + 1 by 3 + 1by 4) to get 6 |
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Answer» -step explanation:Given :-[(1/2)+(1/3)+(1/4)]To find:-What should be added to [(1/2)+(1/3)+(1/4)] to GET 6Solution:-Given number = [(1/2)+(1/3)+(1/4)]Let the number should be added be XOn ADDING X to [(1/2)+(1/3)+(1/4)] then the result => [(1/2)+(1/3)+(1/4)] + XLCM of 2, 3, 4 = 12=> [{(1×6)+(1×4)+(1×3)}/12]+X=> [(6+4+3)/12]+X=> (13/12)+XAccording to the given problemThe result = 6=> (13/12)+X = 6=> X = 6-(13/12)=> X = [(6×12)-13]/12=> X = (72-13)/12=> X = 59/12Therefore the number = 59/12Answer:-The required number for the given problem is 59/12Check:-The given number = [(1/2)+(1/3)+(1/4)]Required number = 59/12Their sum = [(1/2)+(1/3)+(1/4)] +(59/12)=> (6+4+3)/12 + (59/12)=> (13/12)+(59/12)=> (13+59)/12=> 72/12=> 6On adding 59/12 to [(1/2)+(1/3)+(1/4)] to get 6.Verified the given relations in the given problem. |
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