1.

What should be angle between twomirrors that what so ever may be angle of incidence, the incident and reflected rays from the two mirros are parallel to each other:

Answer»

`(pi)/(3)`
`(pi)/(6)`
`(pi)/(2)`
`(pi)/(4)`

Solution :(C ) Total deviation,

`DELTA = (180 - 2i_(1)) + (180 - 2i_(2))`
For RAYS to parallel,
`delta = 180^(@)`
`therefore 360^(@) - 2 (i_(1) + i_(2)) = 180^(@)`
`therefore i_(1) + i_(2) = 90^(@)`
Also in `DeltaABC , (90 - i_(1)) + (90 - i_(2)) + theta = 180^(@)`
or `i_(1) + i_(2) = theta`
`therefore "" theta = 90^(@) = (pi)/(2)`


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