1.

What should be minimum length of tube so that third resonancee can also be heard .

Answer»

`l_(3) =421`
`l_(3) =214`
`l_(3)=124`
NONE of these

Solution :`l_(1) + epsilon = (V)/(4f_(0)) l_(2) + epsilon = (3V)/(4f_(0))` solve both equations and get `epsilon = 1cm`
for third resonance `l_(3) + epsilon = (5V)/(4f_(0)) get l_(3) = 124CM` .


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