What should be the distance between the object in Exercise 9.24 and the magnifying glass if the virtual image of each square in the figure is to have an area of 6.25 mm^(2) . Would you be able to see the squares distinctly with your eyes very close to the magnifier?

What should be the distance between the object in Exercise 9.24 and th

1.	What should be the distance between the object in Exercise 9.24 and the magnifying glass if the virtual image of each square in the figure is to have an area of 6.25 mm^(2) . Would you be able to see the squares distinctly with your eyes very close to the magnifier?
Answer» Solution :Magnification `=sqrt((6.25//1))=2.5` `v=+2.5u` `+(1)/(2.5u)-(1)/(u)=(1)/(10)` i.e., `u=-6cm` `\|v\|=15cm` The VIRTUAL image is CLOSER than the normal NEAR point (25 cm) and cannot be seen by the eye distinctly.

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What should be the distance between the object in Exercise 9.24 and the magnifying glass if the virtual image of each square in the figure is to have an area of 6.25 mm^(2) . Would you be able to see the squares distinctly with your eyes very close to the magnifier?

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