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What should be the distance between the object in Exercise 9.24 and the magnifying glass if the virtual image of each square in the figure is to have an area of 6.25 mm^2. Would you be able to see the squares distinctly with your eyes very close to the magnifier ? |
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Answer» Solution :If we want that area of each square in image is `6.25 mm^2`, it means that linear magnification: `=sqrt((6.25 mm^(2))/(1 mm^(2))) = 2.5 rArr |v|/|u|` or `|v| 2.5 |u|` As focal length of magnifying lens f= + 9 cm `therefore 1/(2.5 mu) -1/u =1/9 rArr u = -5.4 cm` and HENCE, `|v| = 2.5 xx 5.4 = 13.5` cm As now image is being formed at a DISTANCE of 13.5 cm from the eye and this distance is quite less than the least distance of distinct vision (D = 25 cm), hence, EYES will not be able to see the image DISTINCTLY. |
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