1.

What should be the maximum acceptance angle at the aircore interface of an optical fibre if n_(1) and n_(2) are the refractive indices of the core and the cladding, respectively

Answer»

`sin^(-1)(n_(2)//n_(1))`
`1SIN^(-1)sqrt(n_(1)^(2)-n_(2)^(2))`
`[tan^(-1)"(n_(2))/(n_(1))]`
`[tan^(-1)"(n_(1))/(n_(2))]`

Solution :Core of acceptance ANGLE `theta=sin^(-1)sqrt(n_(1)^(2)-n_(2)^(2))`


Discussion

No Comment Found

Related InterviewSolutions