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What should be the minimum magnitude of the magnetic field that must be produced at the equator of earth so that a proton may go round the earth with a speed of 1 × 10^7 ms^-1? Earth’s radius is 6.4 × 10^6 m.(a) 16.63 × 10^-8 T(b) 91.63 × 10^-8 T(c) 1.63 × 10^-8 T(d) 761.63 × 10^-8 TThe question was posed to me in quiz.This key question is from Motion in Combined Electric and Magnetic Field in division Moving Charges and Magnetism of Physics – Class 12 |
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Answer» The CORRECT answer is (c) 1.63 × 10^-8 T |
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