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What type of hybridization is involved in `XeF_2`?A. `sp^3d`B. `dsp^3`C. `sp^3d^2`D. `d^3sp^3`

Answer» Correct Answer - A
The ground state valence shell electron configuration of `Xe` is `5s^2 5p^6`. Out of eight valence electrons, two are used to bond two univalent F atoms and the rest 6 valence `e^(-)s` form 3 lone pairs:
`F-underset(..)X overset(*)(e)-F`
Thus, the steric number of the central `Xe` atom is `2+3=5`. This means five hybrid orbitals are required for bonding in `Xe`. This is possible only through `sp^3d` hybridization. `dsp^3` is excluded because `Xe` is not a d-block element.


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