what volume (in ml)of 0.2M H2SO4 solution should be mixed with the 40m

1.	what volume (in ml)of 0.2M H2SO4 solution should be mixed with the 40ml of 0.1M NaOH SOLUTIONsuchthat the resulting solution has concentration of H2SO4 as (6/55)M
Answer» Solution: We know that resultant molarity is given by Resultant Molarity = (M₁V₁+M₂V₂)/(V₁+V₂) we have M₁ = 0.1, V₁ = 40ml = 0.04 litre M₂ = 0.2, V₂ = ? Now putting the values in above formula we get, (0.1x0.04 + 0.2xV₂)/0.04+V₂ = 6/55 => 0.004+0.2V₂ = (0.24+6V₂)/55 => 0.22+11V₂ = 0.24+6V₂ => 5V₂ = 0.02 => V₂ = 0.004 litre Hence, V₂ = 0.004 litre or 4ml

what volume (in ml)of 0.2M H2SO4 solution should be mixed with the 40ml of 0.1M NaOH SOLUTIONsuchthat the resulting solution has concentration of H2SO4 as (6/55)M

Answer»

Solution: We know that resultant molarity is given by

Resultant Molarity = (M₁V₁+M₂V₂)/(V₁+V₂)

we have M₁ = 0.1, V₁ = 40ml = 0.04 litre

M₂ = 0.2, V₂ = ?

Now putting the values in above formula we get,

(0.1x0.04 + 0.2xV₂)/0.04+V₂ = 6/55

=> 0.004+0.2V₂ = (0.24+6V₂)/55

=> 0.22+11V₂ = 0.24+6V₂

=> 5V₂ = 0.02

=> V₂ = 0.004 litre

Hence, V₂ = 0.004 litre or 4ml