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What volume of 0.2 M `KMnO_(4)` is required to react with 1.58 g of hypo solution `(Na_(2)S_(2)O_(3))` in acidc medium?A. 20 mLB. 10 mLC. 16.6 mLD. 50 mL |
Answer» Correct Answer - B Ew of `Na_(2)S_(2)O_(3)=(158)/(n)(n=1)` `2S_(2)O_(3)^(2-)toS_(4)O_(6)^(2-)+2e^(-)(n=(2)/(2)=1)` ltBrgt `MnO_(4)^(ɵ)=S_(2)O_(3)^(2-)` `mEw-=mEq` `0.2 Mxx5` ("n-factor") `xxV=(1.58)/(158)xx10^(3)` `V=10mL` |
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