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What volume of `3M Na_(2)SO_(4)` must be added to 25mL of 1M `BaCl_(2)` to produce `5g BaSO_(4)`? |
Answer» Correct Answer - a `Na_(2)SO_(4)+BaCl_(2) to BaSO_(4)+2NaCl` `"Number of moles of "BaSO_(4)=("Mass")/("Molar mass")=(5)/(233)=0.0215` `(MV)/(1000)=0.0215 ` `(3xxV)/(1000)=0.0215` V=7.2mL |
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