1.

What volume of `3M Na_(2)SO_(4)` must be added to 25mL of 1M `BaCl_(2)` to produce `5g BaSO_(4)`?

Answer» Correct Answer - a
`Na_(2)SO_(4)+BaCl_(2) to BaSO_(4)+2NaCl`
`"Number of moles of "BaSO_(4)=("Mass")/("Molar mass")=(5)/(233)=0.0215`
`(MV)/(1000)=0.0215 `
`(3xxV)/(1000)=0.0215`
V=7.2mL


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