1.

What volume of `NH_(3)(g) at 27^(@)C` and 1atm pressure will be obtained by therma, decomposition of 26.25g `NH_(3)Cl`?

Answer» Amminomium chloride undergoes decomposition as, `underset(53.5g)underset(1"mol")(NH_(4)Cl(s)) to underset(1"mol")underset(1"mol")(NH_(3)(g))+HCl(g)`
`therefore 53.5g NH_(4)Cl "give 1 mol"NH_(3)`
`=0.5"mole"`
`Pv=Nrt`
`1xxV=0.5xx0.0821xx300`
V=12.315litre


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