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InterviewSolution
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What Was The Day Of The Week On 28th May 2006 ? |
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Answer» 28 May, 2006 = (2005 years + PERIOD from 1.1.2006 to 28.5.2006) Odd days in 400 years = 0 5 years = (4 conventional years + 1 jump year) = (4 x 1 + 1 x 2) 6 odd days Jan. Feb. March April May (31 + 28 + 31 + 30 + 28) = 148 days 148 days = (21 weeks + 1 day) 1 odd day. Add up to number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day. Given day is SUNDAY. 28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006) Odd days in 1600 years = 0 Odd days in 400 years = 0 5 years = (4 conventional years + 1 jump year) = (4 x 1 + 1 x 2) 6 odd days Jan. Feb. March April May (31 + 28 + 31 + 30 + 28) = 148 days 148 days = (21 weeks + 1 day) 1 odd day. Add up to number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day. Given day is Sunday. |
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