1.

What weight of KMnO_(4) will be required to prepare 250 mL of its N/10 solution if eq.wt of KMnO_(4) " is " 31.6 ?

Answer»

SOLUTION :m.e of `KMnO_(4)` solution `= 1/10 xx250 = 25 ""…(Eqn.1)`


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