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What will be angle of first order maxima obtained by Fraunhoffer diffraction by single slit of width0.50 mm ,using light of wavelength 500 nm |
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Answer» `1.5XX10^(-4)` radian `d sin theta_(m)=(2m+1)(lambda)/(2)` Taking `m=1` `sin theta_(1)=(3lambda)/(2d)` `=(3xx5xx10^(-7))/(5xx10^(-4))=3xx10^(-3)` RAD if `theeta_(1)` is too small `sin theta_(1)~~ theta_(1)` `theta_(1)=3xx10^(-3)` radian |
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