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What will be maximum value of wavelength by which photo-electric emission can be obtained on metal surface with work function of 3.2 eV? (h=6.625xx10^(-34) Js) |
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Answer» 1988Å `therefore lambda_(0)=(hc)/(phi_(0))=(6.625xx10^(-34)xx3xx10^(8))/(3.2xx1.6xx10^(-19))` `lambda_(0)=3.881835xx10^(-7)` `therefore lambda_(0)~~3882xx10^(-10)m` `therefore lambda_(0)=3882 Å` |
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