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What will be the acceleration due to gravity at a distance of 3200 km below the surface of the earth ? (Take `R_(e)=6400` km)

Answer» Correct Answer - `4.9 m//s^(2)`
Hint : `g=g(1-(d)/(R_(e)))` (Take d = 3200 km and `R_(e)=6400` km)


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