1.

What will be the change in internal energy when 12 kJ of work is done on the system and 2 kJ of heat is given by the system?A. `+10kJ`B. `-10kJ`C. `+5kJ`D. `-5kJ`

Answer» Correct Answer - A
Heat evolved = -2 kJ
Work done on the system `=+12kJ`
`DeltaU=q+w=-2+12=+10k`


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