1.

What will be the diffraction angle of first order maxima in diffraction obtained due to light of wavelength 55nm and width of slit 0.55 mm ?

Answer»

`0.0015` radian
`0.00015` radian
`0.003` radian
`0.0010` radian

Solution :For first order maxima `d sin theta_(m)=((2m+1)lambda)/(2)`
`d sin theta_(1)=(3lambda)/(2) "" lambda=5xx10^(-7)m`
`d=55xx10^(-5)m`
`:. sintheta_(1)=(3lambda)/(2D)=(3)/(2)XX(55xx10^(-9))/(55xx10^(-5))`
`=(3)/(2)xx10^(-4)=0.00015` radian


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