1.

What will be the e.m.f. of the given cell? Pt|H_(2)(P_(1))|H^(+)(aq)|H_(2)(P_(2))|Pt

Answer»

`(RT)/(F)"ln"(P_(1))/(P_(2))`
`(RT)/(2F)"ln"(P_(1))/(P_(2))`
`(RT)/(F)"ln"(P_(2))/(P_(1))`
none of these

Solution :`R.H.S.:2H^(+)+2e^(-)toH_(2)(P_(2))`
`L.H.S.:H_(2)(P_(1))to2H^(+)+2e^(-)`
Overall REACTION: `H_(2)(P_(1))toH_(2)(P_(2))`
`E=E^(@)-(RT)/(nF)"ln"(P_(2))/(P_(1))=0-(RT)/(2F)"ln"(P_(2))/(P_(1))=(RT)/(2F)"ln"(P_(1))/(P_(2))`


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