1.

What will be the emf of given cell - Pt |H_(2) (P_(1)) | H_((aq))^(+) | | H_(2)(P_(2))|Pt ?

Answer»

`(RT)/(2F) "LOG"_(e) (P_(1))/(P_(2))`
`(RT)/(F) "log"_(e) (P_(1))/(P_(2))`
`(RT)/(F) "log"_(e) (P_(2))/(P_(1))`
`(RT)/(2F) "log"_(e)(P_(2))/(P_(1))`

Solution :At anode , `H_(2)(P_(1)) to 2 H^(+) + 2E^(-)`
At cathode ` 2H^(+) + 2e to H_(2)(P_(2))`
`E_("cathode") = (-RT)/(2F) "ln" (P_(2))/([H^(+)]^(2))` and
`E_("anode") = (-RT)/(2F) "ln" ([H^(+)]^(2))/(P_(1))`


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