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What will be the equation of normal to the hyperbola 3x^2 – 4y^2 = 12 at the point (x1, y1)?(a) 3x1y + 4y1x + 7x1y1 = 0(b) 3x1y + 4y1x – 7x1y1 = 0(c) 3x1y – 4y1x – 7x1y1 = 0(d) 3x1y – 4y1x + 7x1y1 = 0This question was posed to me by my school principal while I was bunking the class.My question is based upon Calculus Application topic in section Application of Calculus of Mathematics – Class 12 |
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Answer» Correct answer is (B) 3x1y + 4y1x – 7x1y1 = 0 |
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