

InterviewSolution
Saved Bookmarks
1. |
What will be the escape speed from a planet having mass 8 times that of earth and diameter 4 times that of the earth ? `[v_(e)=11.2 km//s]` |
Answer» `v_(p) = ?` Now, `v=sqrt((2GM)/(R ))` `therefore (v_(p))/(v_(e))=sqrt((M_(p))/(M_(e))xx(R_(e))/(R_(p)))=sqrt((8M_(e))/(M_(e))xx(R_(e))/(4R_(e)))` `therefore v_(p)=sqrt(2)v_(e)` `=sqrt(2)xx11.2` `=15.84 km//s` . |
|