What will be the general solution of differential equation for 2^x – y dx + 2^y – x dy = 0?(a) 2^2x + 2^2y = c(b) 2(2^2x + 2^2y) = c(c) 3(2^2x + 2^2y) = c(d) 4(2^2x + 2^2y) = cThis question was posed to me during a job interview.My question is from Linear First Order Differential Equations in portion Differential Equations of Mathematics – Class 12

What will be the general solution of differential equation for 2^x –

1.	What will be the general solution of differential equation for 2^x – y dx + 2^y – x dy = 0?(a) 2^2x + 2^2y = c(b) 2(2^2x + 2^2y) = c(c) 3(2^2x + 2^2y) = c(d) 4(2^2x + 2^2y) = cThis question was posed to me during a job interview.My question is from Linear First Order Differential Equations in portion Differential Equations of Mathematics – Class 12
Answer» RIGHT ANSWER is (a) 2^2x + 2^2y = c To explain I would say: We have, 2^X – y DX + 2^y – x dy = 0 Or, (2^x/2^y)dx + (2^y/2^x)dy = 0 Integrating both sides, ∫2^2xdx + ∫2^2ydy = k Taking k = c/2log2 as, k, c and 2log2 are constant. Or, 2^2x/2log2 + 2^2y/2log2 = c/2log2 Or, 2^2x + 2^2y = c

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