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What will be the melting point of KCl if enthalpy change for the reaction is `"7.25 J mol"^(-1)` and entropy change is `"0.007 J K"^(-1)"mol"^(-1)`?A. 1835.2 KB. 173 KC. 1035.7 KD. 1285.2 K |
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Answer» Correct Answer - C `T=(DeltaH)/(DeltaS)=(7.25)/(0.007)= 1035.7 K` |
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