Related InterviewSolutions

• On diving `0.46` by `15.374`, the atual answer is `0.029236`. The correctly reported answer will beA. `0.02`B. `0.029`C. `0.0292`D. `0.02924`
• Match the following `{:("(i)","88 g of CO"_(2),"(a)","0.25 mol"),("(ii)",6.022 xx 10^(23)" molecules of "H_(2)O,"(b)","2 mol"),("(iii)","5.6 litres of O"_(2)" at STP","(c)","1 mol"),("(iv)","96 g of O"_(2),"(d)",6.022xx10^(23)"molecules"),("(v)","1 mole of any gas","(e)","3 mol"):}`A. i-a,ii-b,iii-d,iv-c,v-eB. i-b,ii-c,iii-a,iv-e,v-dC. i-c,ii-b,iii-d,iv-d,v-eD. i-d,ii-e,iii-a,iv-b,v-b
• In Balancing the reaction `XZn + NO_(3)^(-) +YH^(+) rarr XZn^(2+)+NH_(4)^(+) + ZH_(2)O, XY` & Z areA. 4,10,3B. 3,8,3C. 3,10,3D. 4,3,10
• 2.16 grams of Cu on reaction with `HNO_(3)` followed by ignition of the nitrate gave 2.7 gm of copper oxide. In another experiment 1.15 gm of copper oxide upon reduction with hydrogen gave 0.92 gm of copper. This data illustrate the law ofA. Multiple ProportionsB. Definite ProportionsC. Reciprocal proportionsD. Conservation of mass
• Irrespective of the source, pure sample of water always yields `88.89%` mass of oxygen and `11.11%` mass of hydrogen. This is explained by the law ofA. Conservation of massB. Constant proportionsC. Multiple proportionsD. Constant volume
• The mass of nitrogen per gram in hydrazine is exactly one and half the mass of nitrogen in the compound ammonia. The fact illustrates theA. Law of conservation of massB. Multiple valency of nitrogenC. Law of multiple proportionD. Law of definite Portin
• Which of the following statements indicates that law of multiple proportion is being followed?A. Sample of carbon dioxide taken from any source will always have carbon and oxygen in the ratio 1:2B. Carbon forms two oxides namely `CO_(2)` and `CO` where masses of oxygen which combine with fixed mass of carbon are in the simple ratio 2:1C. When magnesium burns in oxygen, the amount of magnesium taken for the reaction is equal to the amount of magnesium in magnesium oxide formedD. At constant temperature and pressure 200 mL of hydrogen will combine with 100 mL oxygen to produce 200 mL of water vapour.
• Statement Addition of water to a solution containing solute and solvent changes its normality or molarity only. Explanation The milli-equivalent and milli-moles of solutes are not changed on dilution.A. Statement -1 is True, Statement -2 is True, Statement -2 is a correctB. Statement -1 is True, Statement -2 is True, statement -2 is NOT a correct explanation for Statement-6C. Statement-1 is True, Statement-2 is FalseD. Statement-1 is False, Statement-2 is True
• What will be the molality of the solution containing 18.25 g of HCl gas in 500 g of water?A. 0.1mB. 1MC. 0.5mD. 1m
• The empirical formula and molecule mass of a compound are `CH_(2)O` and 180g respectivel. What will be the molecular formula of the compound?A. `C_(9)H_(18)O_(9)`B. `CH_(2)O`C. `C_(6)H_(12)O_(6)`D. `C_(2)H_(4)O_(2)`