What will be the motion of the conductor of the previous problem, if a resistor of resistance R is connected into the circuit instead of the capacitor? Neglect the resistance of the conductors.

What will be the motion of the conductor of the previous problem, if a

1.	What will be the motion of the conductor of the previous problem, if a resistor of resistance R is connected into the circuit instead of the capacitor? Neglect the resistance of the conductors.
Answer» Solution :The forces acting on a FALLING conductor are tho force of gravity mg directed downwards and the Ampere force F= iBi directed upwards. By Ohm.s law `i=epsi//R` and the induced e.m.f. is `epsi=Blv`. HENCE the Ampera force is `F= B^2l^2u//R.` The equation of motion of the condutor is `a=(mg-F)/(m)=g-(B^2l^2v)/(m R)` After a certain moment of time the acceleration becomes ZERO and the conductor CONTINUES to fall uniformly at a constant speed (compare with PROBLEM 5.13).

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What will be the motion of the conductor of the previous problem, if a resistor of resistance R is connected into the circuit instead of the capacitor? Neglect the resistance of the conductors.

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