1.

What will be the orbital speed from a planet of mass `10^(30)` kg and and of radius `10^(8)` m ?

Answer» `V_(0)=sqrt((GM)/(R ))`
`therefore V_(0)=sqrt((6.67xx10^(-11)xx10^(30))/(10^(8)))`
`therefore V_(0)=sqrt(66.7xx10^(10))`
`= 8.1xx10^(5)` m/s.


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