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What will be the orbital speed from a planet of mass `10^(30)` kg and and of radius `10^(8)` m ? |
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Answer» `V_(0)=sqrt((GM)/(R ))` `therefore V_(0)=sqrt((6.67xx10^(-11)xx10^(30))/(10^(8)))` `therefore V_(0)=sqrt(66.7xx10^(10))` `= 8.1xx10^(5)` m/s. |
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