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What will be the photon energy for a wavelength of 5000 angstroms, if the energy of a photon corresponding to a wavelength of 7000 angstroms is 4.23 × 10^-19 J?(a) 0.456 eV(b) 5.879 eV(c) 3.701 eV(d) 1.6 × 10^-19 eVThis question was addressed to me during an interview.This interesting question is from Particle Nature of Light : The Photon topic in chapter Dual Nature of Radiation and Matter of Physics – Class 12 |
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Answer» RIGHT answer is (C) 3.701 eV For EXPLANATION: \(\frac {E_2}{E_1} = \frac {\lambda_1}{\lambda_2}\) \(\frac {\lambda_1}{\lambda_2} = \frac {1.4 \times 4.23 \times 10^{-19}}{1.6 \times 10^{-19}}\) eV \(\frac {\lambda_1}{\lambda_2}\) = 3.701 eV |
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