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What will be the pressure exerted by a mixture of `3.2 g` of methane and `4.4 g` of methane and `4.4g` of carbon dixide contained in a `9 dm^(3)` flask at `27^(@)C` ? . |
Answer» `PV =nRT` `n =n_(CH_4) + n_(CO_2) = (3.2)/(16) + (4.4)/(44) =0.3` `V =9dm^(3) =9litre` `:. P xx 9 = 0.3 xx 0.082 xx 300` `:. P =0.82 atm = 0.82 xx 1.013xx 10^(5) Pa` `= 8.31 xx 10^(4) Pa` . |
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