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What will be the pressure of the gas mixture when 0.5 litre of `H_(2)` at 0.8 bar and 2.0 litre of oxygen at 0.7 bar are introduced in a 1 litre vessel at `27^(@)C` . |
Answer» For `H_(2) n = (PV)/(RT) = (0.8 xx 0.5)/(RT) = (0.4)/(RT)` For `O_(2) n = (0.7 xx 2.0)/(RT) = (1.4)/(RT)` `:.` Total moles in mixture ` =(0.4)/(RT) + (1.4)/(RT) = (1.8)/(RT)` Using `PV = nRT` for 1 litre container Now `P_(mixture) xx 1 = (1.8)/(RT) xx RT = 1.8` bar |
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